Mar 6, 2018 · I've seen the pattern ABA', where A and B are matrices, and ' stands for the transpose, many times so I want to know if there is an intuition for this pattern. I did some development to see …

May 19, 2017 · Square matrices, ABA = A? Ask Question Asked 8 years, 7 months ago Modified 8 years, 7 months ago

How does one prove that ABA−1 = B A B A 1 = B given that A is an invertible matrix? [closed] Ask Question Asked 7 years, 11 months ago Modified 7 years ago

May 4, 2016 · I have been learning about matrix symmetry and came up with a question that I can't seem to prove. The idea is that the product of $ABA^T$ is a symmetric matrix.

Apr 17, 2020 · I know in group theory, the operation ABA−1 A B A 1, i.e. the element A multiplied by the element B, and then multiplied by the inverse of A, is called conjugation. When dealing with matrices, …

Sep 17, 2020 · I don't see how to differentiate $ABA^T$ with respect to $A$ where $A$ and $B$ are $n\times n$ matrices. I know it's going to be a rank-4 tensor, but what exactly will it be?

Apr 19, 2023 · Conjugation in group theory, related to matrix similarity in linear algebra Conjugation (group theory), the image of an element under the conjugation homomorphisms Conjugate closure, …

Jul 22, 2017 · X = ABAT X = A B A T, X is a square matrix and A is rectangular matrix and I need to solve matrix B by enforcing it as a diagonal matrix. For non-singular matrix we can write B as …

Feb 27, 2023 · What can I say about the rank of $ABA^T$ under these circumstances, if anything? Are there reasonable conditions besides $B$ positive definite symmetric which will make this product …

Feb 19, 2020 · Is it true ABA = A ⇒ BAB = B A B A = A ⇒ B A B = B ? A A and B B are nonzero matrice. If A A is invertible the statement is obvious. What if A A is singular?